WebJul 3, 2024 · First, get the first day of the current month: SELECT CAST (DATEADD (DAY, 1 - DAY (GETDATE ()), GETDATE ()) AS DATE) Then, get the first day of the next … datepart The part of date to which DATEADD adds an integer number. This table lists all valid datepartarguments. number An … See more dayofyear, day, and weekdayreturn the same value. Each datepartand its abbreviations return the same value. If the following are true: 1. … See more The return value data type for this method is dynamic. The return type depends on the argument supplied for date. If the value for date is a string literal date, DATEADD returns a datetime value. If another valid input … See more The number argument cannot exceed the range of int. In the following statements, the argument for number exceeds the range of int by 1. … See more
How to get First Day of Month - CodeProject
WebJul 15, 2015 · First of previous month =DateSerial (Year (Now), Month (Now)-1, 1) Last day of previous month =DateSerial (Year (Now ()), Month (Now ()),"0") The interesting thing is that in visual studio 2010 I get 30/06/2015 returned while when in SQL report server I get 29/06/2015 - does anyone know why? Wednesday, July 15, 2015 9:38 AM WebOct 25, 2016 · So what this does is: (1) Get the number of months between the current date and 0. (2) Add that number of months back to 0. This sets the day part to 1 (first day of … brielle at seaview staten island
Re: DAX to sum only the partial sales of the previous year
WebDB2 date functions are the scalar functions provided by IBM to handle and manipulate the date values in the DB2 database. The availability of these date and time functions in DB2 makes it very effective and easy to manipulate the date and time-related values. WebJan 16, 2014 · DECLARE @EndDate DATETIME DECLARE @StartDate DATETIME SET @EndDate = dateadd(month, datediff(month,0, CURRENT_TIMESTAMP)-6,0); SET @StartDate = DATEADD(month, - 6, @EndDate) --SELECT * FROM tbl_name WHERE column_name>=@startdate and column_name<@EndDate select @startdate as … WebSep 1, 2024 · If that's the case and they'll always be in the format 'yyyy-MM-dd', you can just take the first 8 characters and add '01': left (MyStringValue, 8) + '01' If you're working … brielle and ariana biermann